Date: 2026-06-06
Time: 19:43
xor-operation-in-an-array/solution.pyThis file solves LeetCode 1486 — XOR Operation in an Array. It owns the computation of the bitwise XOR across a virtual array nums where nums[i] = start + 2*i for i in [0, n). The array is never materialized — the solution computes the XOR on the fly.
Solution.xorOperation(self, n: int, start: int) -> int
The single method. Contract:
n (array length, 1 <= n <= 1000) and start (starting value, 0 <= start <= 1000, even per the problem constraints).n elements start, start+2, start+4, ..., start+2*(n-1).Accumulator pattern. result is initialized to 0 (the identity element for XOR) and each element is folded in via ^=. This is the standard reduce-over-XOR idiom — equivalent to functools.reduce(operator.xor, (start + 2*i for i in range(n))) but more explicit.
Virtual array. The problem defines nums[i] = start + 2*i, but the solution never allocates the array. Each element is computed inline inside the loop. This keeps space at O(1).
Imports: None. Pure computation with no library dependencies.
Imported by: The xor-operation-in-an-array/test_solution.py file imports this Solution class. The massive "Imported By" list in the prompt is an artifact of the test harness structure — those other test files don't actually import *this* solution; they share a common test runner pattern.
1. Initialize result = 0.
2. For each i in [0, n), compute the element start + 2*i and XOR it into result.
3. Return result.
Concrete trace: n=4, start=3 produces elements 3, 5, 7, 9.
0 ^ 3 = 33 ^ 5 = 66 ^ 7 = 11 ^ 9 = 88.result after iteration i equals the XOR of the first i+1 elements.start.None. The method assumes valid inputs per the LeetCode constraint guarantees. No bounds checking, no type validation. This is appropriate for a competitive programming solution where the caller (the judge) guarantees valid input.