Date: 2026-06-06
Time: 19:26
This file solves LeetCode 2558: Take Gifts From the Richest Pile. It owns the single responsibility of simulating k rounds of a process where you repeatedly pick the largest pile, take most of its gifts (leaving behind the integer square root), and return the total remaining.
giftsRemaining(gifts, k) -> intThe sole public function. Contract:
gifts — a list of non-negative integers representing pile sizes; k — number of rounds to simulate.k rounds of reducing the largest pile to floor(sqrt(max)).Max-heap via negation. Python's heapq is a min-heap. The code negates all values (-g) to simulate max-heap behavior — a standard Python idiom. Every push/pop inverts the sign on the way in and out.
In-place simulation. Rather than sorting or scanning for the max each round, the heap gives O(log n) extraction and reinsertion per round, making the overall complexity O(n + k log n) instead of O(k * n).
Imports:
heapq — heap operations (heapify, heappop, heappush)math — math.isqrt for integer square root (exact floor, no float truncation issues)Imported by: The corresponding take-gifts-from-the-richest-pile/test_solution.py. The long "Imported By" list in the prompt is an artifact of the test harness importing a shared fixture, not this solution file itself.
1. Build heap: Negate every gift value and heapify in O(n).
2. Simulate k rounds: Each round pops the max (smallest negative), computes isqrt, pushes the negated result back.
3. Sum: Negate the sum of the heap to get the true total.
Concrete trace with gifts=[25, 64, 9], k=1:
[-64, -25, -9]-64 → max_val=64 → isqrt(64)=8 → push -8 → heap is [-25, -8, -9]-(-25 + -8 + -9) = 42math.isqrt guarantees an exact integer floor — no floating-point rounding surprises that int(math.sqrt(...)) can produce for large values.gifts is non-empty and k >= 0. No explicit validation; LeetCode constraints guarantee this.None. The function trusts its inputs per LeetCode constraints. Passing an empty list would cause heappop to raise IndexError; passing negative gift values would produce incorrect results since isqrt rejects negatives with a ValueError.