Date: 2026-06-06
Time: 17:43
maximum-repeating-substring/solution.pyThis file implements LeetCode problem 1668 — Maximum Repeating Substring. It provides a single function that determines the highest value of k such that word repeated k times is a substring of sequence. It's one of ~500+ solution files in the leetcode-implementations repo, each owning exactly one problem's solution.
longestAwesomeSubstring(sequence, word) -> int — The sole public function. Despite the misleading name (it has nothing to do with "awesome substrings"), it solves the maximum repeating substring problem.
sequence and a string word, returns the largest integer k >= 0 such that word * k (i.e., word concatenated k times) appears as a contiguous substring in sequence. Returns 0 if word itself doesn't appear in sequence.Linear search from below: The algorithm starts at k = 0 and increments, checking word * (k+1) in sequence at each step. This is a brute-force approach that leverages Python's built-in in operator for substring matching. The loop terminates at the first k where the next repetition isn't found, which is correct because if word * n isn't a substring, neither is word * (n+1).
Python string multiplication idiom: word * (k + 1) constructs the repeated string. This is idiomatic Python and avoids manual concatenation.
Imports: None — the solution is self-contained with no external dependencies.
Imported by: The testsolution.py files listed in the "Imported By" section are clearly an artifact of the repo's test infrastructure — those hundreds of test files don't actually import *this* solution. Only maximum-repeating-substring/testsolution.py meaningfully imports this function. The rest appear to be a bug in the dependency analysis tooling (likely every test file imports a common harness that transitively references all solutions, or the import graph was generated incorrectly).
1. Initialize k = 0.
2. Build the candidate string word * (k + 1).
3. Check if that candidate exists in sequence using Python's in operator (which uses a variant of Boyer-Moore/Horspool under the hood in CPython).
4. If found, increment k and repeat.
5. If not found, return k — the last successful repetition count.
len(word) characters each iteration. Since sequence is finite, the loop must terminate — the candidate will eventually exceed len(sequence).k because it starts from 0 and counts up. There are no gaps — if word * 3 is a substring, then word * 2 and word * 1 are also substrings (they're prefixes of word * 3).None. The function assumes valid string inputs per the LeetCode contract. Empty word would cause an infinite loop since "" in sequence is always True — but the problem constraints guarantee 1 <= len(word).
The function is named longestAwesomeSubstring, which is the name for a different LeetCode problem (1542 — Find Longest Awesome Substring). The correct name for problem 1668 would be something like maxRepeating. This is likely a copy-paste error from the code generation pipeline.
n = len(sequence) and kmax is the answer. Each in check is O(n) and the candidate grows linearly, so more precisely O(kmax^2 * len(word) + kmax * n). In practice k_max is small given the problem constraints (sequence length up to 100).maximum-repeating-substring/test_solution.py — See what edge cases are tested (empty results, single-char words, overlapping patterns)maximum-repeating-substring/review.md — Check if the naming issue was flagged during reviewdetect-pattern-of-length-m-repeated-k-or-more-times/solution.py — Related problem involving repeated patterns; compare approachesfunction-naming-conventions — Audit whether other solutions have mismatched function names from the generation pipelinemaximum-repeating-substring/plan.md — Understand whether alternative approaches (binary search on k, KMP) were consideredmax-repeating-uses-linear-scan — The solution finds maximum k by incrementing from 0 and checking word * (k+1) in sequence, not by binary search or string algorithmmax-repeating-wrong-function-name — The function is named longestAwesomeSubstring but solves LeetCode 1668 (Maximum Repeating Substring), not 1542 (Longest Awesome Substring)max-repeating-no-empty-word-guard — The function has no guard against empty word input, which would cause an infinite loop; it relies on LeetCode's constraint that len(word) >= 1max-repeating-no-imports — The solution has zero imports and depends only on Python builtins (str._mul, str.contains_)