Date: 2026-06-06
Time: 17:18
largest-triangle-area/solution.pyThis file solves LeetCode 812 — Largest Triangle Area. Given a list of 2D points, it finds the maximum area among all triangles formed by any three of those points. It's a brute-force combinatorial geometry solution.
Solution.largestTriangleArea(self, points: list[list[int]]) -> float
The single method. Takes a list of [x, y] coordinate pairs and returns the largest triangle area as a float.
The area computation uses the Shoelace formula (a.k.a. the surveyor's formula), which computes a triangle's area from vertex coordinates without needing side lengths or angles:
area = |x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)| / 2
This is equivalent to half the absolute value of the cross product of two edge vectors, which gives the area of the parallelogram they span.
for (x1, y1), (x2, y2), (x3, y3) in combinations(points, 3) destructures each 3-combination into six named scalars in one shot, keeping the formula readable.max_area with a comparison rather than collecting all areas and calling max(), avoiding unnecessary allocation.itertools.combinations — generates all unordered 3-element subsets.largest-triangle-area/test_solution.py directly. The massive "Imported By" list in the prompt is an artifact of how the repo's test harness discovers solution modules — those test files don't actually call largestTriangleArea.1. Initialize max_area = 0.0.
2. For each triple of points from combinations(points, 3):
(x1, y1), (x2, y2), (x3, y3).max_area if this area is larger.3. Return max_area.
abs() makes the formula orientation-independent — the vertex winding order doesn't matter.max_area starts at 0.0, so if every triple is degenerate, the function returns 0.0.None. The function trusts its input matches the LeetCode contract (at least 3 points, integer coordinates). Passing fewer than 3 points would cause combinations to yield nothing, and the function would silently return 0.0.