Date: 2026-06-06
Time: 16:48
find-winner-on-a-tic-tac-toe-game/solution.pySolves LeetCode 1275: Find Winner on a Tic Tac Toe Game. Given a sequence of moves on a 3x3 board, determines the game state: whether player A or B won, whether it's a draw, or whether the game is still pending.
validateBinaryTreeNodes(moves) — Misnamed function (likely a copy-paste artifact from another solution). Despite the name, it implements tic-tac-toe winner detection.
moves: list[list[int]] — ordered [row, col] pairs. Even-indexed moves belong to player A (value 1), odd-indexed to player B (value 2)."A ", "B ", "Draw ", "Pending " (note trailing spaces — matches LeetCode's expected output format).wins — A hardcoded list of all 8 winning lines: 3 rows, 3 columns, 2 diagonals. Each line is a list of (row, col) tuples.
grid — A 3x3 matrix initialized to zeros, representing the board. 0 = empty, 1 = A, 2 = B.
player = 1 if i % 2 == 0 else 2 encodes the A-then-B turn order without separate state.Imports: None — pure Python, no standard library usage.
Imported by: The test_solution.py in the same directory, plus — per the "Imported By" list — hundreds of unrelated test files. That massive import list is almost certainly a tooling artifact (e.g., a shared test harness or auto-generated import), not a real dependency on this solution's logic.
1. Initialize a 3x3 zero grid.
2. Iterate through moves with index i:
i % 2.3. After all moves are played: return "Draw " if 9 moves were made (board full), otherwise "Pending ".
"A ", not "A").None. Invalid input (out-of-range coordinates, overlapping moves) will silently produce wrong results or raise an IndexError. This is typical for LeetCode solutions where input validity is guaranteed by the problem constraints.