{"id":"stack-queue-costly-push-strategy","text":"Push is O(n) due to rotating n-1 elements behind the new element; pop, top, and empty are all O(1). This is the costly-push variant, preferred when reads outnumber writes.","truth_value":"IN","source":"entries/2026/06/06/implement-stack-using-queues-solution.md","source_url":"","source_hash":"","justifications":[],"dependents":[],"metadata":{},"created_at":"","updated_at":"","reviewed_at":"","verified_at":"","retracted_at":"","explanation":{"steps":[{"node":"stack-queue-costly-push-strategy","truth_value":"IN","reason":"premise"}]}}