{"id":"min-max-game-linear-total-work","text":"Total comparisons across all rounds is O(n) due to geometric halving (n/2 + n/4 + ... = n - 1).","truth_value":"IN","source":"entries/2026/06/06/min-max-game-solution.md","source_url":"","source_hash":"","justifications":[],"dependents":[],"metadata":{},"created_at":"","updated_at":"","reviewed_at":"","verified_at":"","retracted_at":"","explanation":{"steps":[{"node":"min-max-game-linear-total-work","truth_value":"IN","reason":"premise"}]}}