early-exit-on-impossible-partition

Status: IN

The decomposable-substrings solution short-circuits to `False` on the first character run with `length % 3 == 1`, since no valid tiling of 2s and 3s can cover that remainder without exceeding the exactly-one-two constraint.

Source: entries/2026/06/06/check-if-string-is-decomposable-into-value-equal-substrings-solution.md

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